AP POLYCET 2026 Download Answer Key & Question Paper [PDF] AP POLYCET 2026 Official Key [Soon]. AP Polycet 2026 Exam is conducted on 25th April 2026 from 11 am to 1pm. The AP POLYCET Official Key is going to be released by SBTETAP. Mean while, the experts has released the AP POLYCET 2026 Key basing on the POLYCET 2026 Question Paper. Candidates can check the Answers with the Key and have an Idea about their Marks.
AP POLYCET Answer Key 2026 - SBTET, AP will release the AP POLYCET 2026 answer key a few days. Download the AP POLYCET 2026 Question Paper, AP POLYCET 2026 Answer Key PDF Below.
![AP POLYCET 2026 Answer Key Download PDF [Released]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEisApWCU2ICcaZkpxKlaI0Ynv4EBwqQ8nfXfW815_SEGdI26VayTY6aT7bDPe1jkaGbBXWMlU6MVd8nCReUhDLr-OhVtRVvV02X_k-RP4cIU6-Z-5SCxFCMQbju0Syj6jz_EU94AA0iPbWEWB2PnxaZlt_8APXOuTdw2G1eA-NJZ8r2wkzFgn_byiGHeWE/s16000/AP%20POLYCET%202026%20Answer%20Key.jpg "AP POLYCET 2026 Answer Key Download PDF [Released]")
The details of the exam, including its duration, the total number of questions, and the marking scheme, are important for candidates to understand how their performance might be evaluated. The duration of the exam was set at two hours.
To submit objections, you have to pay a certain amount of fee and also to board may request valid proof of your objection. After receiving objection the officials will review it and publish the final solution key based on changes made in it.
AP POLYCET Answer Key 2026 - SBTET, AP will release the AP POLYCET 2026 answer key a few days. Download the AP POLYCET 2026 Question Paper, AP POLYCET 2026 Answer Key PDF Below.
AP POLYCET 2026 Answer Key Download, Question Paper Download. The State Board of Technical Education and Training, Andhra Pradesh has completed the POLYCET examination. The Andhra Pradesh Polytechnic Common Entrance Test was conducted on April 25, 2026.
Many students seeking admission to diploma courses in engineering and non-engineering fields offered by polytechnics across Andhra Pradesh have participated in this exam.
After the condition of the entrance test, the participants are looking for the AP POLYCET Answer Key that will be released online through the official portal of the Technical Education and Training Board. The Board will release the solution key within 2 weeks of the examination.
![AP POLYCET 2026 Answer Key Download PDF [Released]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEisApWCU2ICcaZkpxKlaI0Ynv4EBwqQ8nfXfW815_SEGdI26VayTY6aT7bDPe1jkaGbBXWMlU6MVd8nCReUhDLr-OhVtRVvV02X_k-RP4cIU6-Z-5SCxFCMQbju0Syj6jz_EU94AA0iPbWEWB2PnxaZlt_8APXOuTdw2G1eA-NJZ8r2wkzFgn_byiGHeWE/s1600/AP%20POLYCET%202026%20Answer%20Key.jpg "AP POLYCET 2026 Answer Key Download PDF [Released]")
AP POLYCET 2026 Exam Details
AP POLYCET 2026 Answer Key Download, Question Paper Download. The State Board of Technical Education and Training, Andhra Pradesh has completed the POLYCET examination. The Andhra Pradesh Polytechnic Common Entrance Test was conducted on April 25, 2026.Many students seeking admission to diploma courses in engineering and non-engineering fields offered by polytechnics across Andhra Pradesh have participated in this exam.
After the condition of the entrance test, the participants are looking for the AP POLYCET Answer Key that will be released online through the official portal of the Technical Education and Training Board. The Board will release the solution key within 2 weeks of the examination.
27న పాలిసెట్ ప్రాథమిక కీ విడుదల
పాలిటెక్నిక్ డిప్లొమాలో ప్రవేశాలకు శనివారం నిర్వహించిన పాలిసెట్ పరీక్షకు 92% మంది అభ్యర్థులు హాజరయ్యారు.
రాష్ట్రవ్యాప్తంగా ప్రవేశాల కోసం 1,77,581 మంది అభ్యర్థులు దరఖాస్తు చేసుకోగా.. 1,63,008 మంది పరీక్ష రాశారు. ప్రశ్నపత్రానికి సంబంధించిన ప్రాథమిక 'కీ'ని ఈ నెల 27న విడుదల చేయనున్నారు.
ఫలితాలను మే 5న వెల్లడించేందుకు చర్యలు తీసుకుంటున్నట్లు ఉన్నత విద్య కమిషనర్ నారాయణ భరత్ గుప్తా తెలిపారు.
AP POLYCET 2026 Exam Overview
The AP POLYCET is designed to assess the aptitude of candidates in Physics, Chemistry, and Mathematics to determine their suitability for polytechnic courses. The paper follows a specific pattern and is typically conducted offline as an objective type test.The details of the exam, including its duration, the total number of questions, and the marking scheme, are important for candidates to understand how their performance might be evaluated. The duration of the exam was set at two hours.
| Sections | Subject | Total Questions/ Marks |
|---|---|---|
| Section A | Mathematics | 50 |
| Section B | Physics | 40 |
| Section C | Chemistry | 30 |
| Particulars | Details |
| Exam Name | AP POLYCET 2026 (Polytechnic Common Entrance Test) |
| Mode of Exam | Offline (Pen and Paper based - OMR Sheet) |
| Type of Questions | Multiple Choice Questions (MCQs) |
| Total Number of Questions | 120 |
| Subjects Covered | Mathematics – 50 Questions, Physics – 40 Questions, Chemistry – 30 Questions |
| Total Marks | 120 Marks |
| Duration of Exam | 2 Hours (120 Minutes) |
| Medium of Exam | Telugu, English, and Urdu |
| Marking Scheme | +1 mark for each correct answer |
| Negative Marking | No negative marking |
Download the POLYCET 2026 Answer Key [by APTEACHERS]
The AP POLYCET 2026 preliminary answer key will be published on the official website, allowing applicants to raise objections within a specified timeframe via email. Following the review of objections, the final answer key will be released alongside the exam results. Candidates can use the answer key to estimate their scores before the results are announced.AP POLYCET 2026 Mathematics Key with Short Explanations [Set B]
This Key is prepared by APTEACHERS within the short span of time. Hence there may be some errors. Hence verify with the official Answer Key Imp Note: Copying the content is strictly prohibited. This is a property of APTEACHERS.IN Website| Q. No. | Answer | Explanation/Hint |
| 1 | (4) 0∘ | Using 2sinAcosA=2sinA, we get cosA=1, so A=0∘.
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| 2 | (3) 1 | This is the identity sin(60∘+30∘)=sin90∘=1.
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| 3 | (4) 40/3 | tan60∘=40/d⟹3=40/d⟹d=40/3. +1
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| 4 | (4) 30∘ | Let height be h, shadow is 3h. tanθ=h/(3h)=1/3⟹θ=30∘.
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| 5 | (2) 1/52 | There is only 1 Queen of Diamonds in a deck of 52.
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| 6 | (4) 1/2 | Vowels in 'MOBILE' are O, I, E (3 out of 6). 3/6=1/2.
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| 7 | (2) 14 | 400×0.035=14. |
| 8 | (1) 0.95 | P(not E)=1−P(E)=1−0.05=0.95.
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| 9 | (2) 69.43 | Calculated using ∑fixi/∑fi from the provided table. +1
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| 10 | (1) 3.286 | Using the Mode formula l+(2f1−f0−f2)f1−f0×h on the 3-5 class. +1
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| 11 | (3) 55-60 | Median class is where cumulative frequency reaches N/2=15.
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| 12 | (4) 1.35 | Arranged: 1.02, 1.2, 1.3, 1.35, 1.4, 1.6, 1.7. Middle value is 1.35.
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| 13 | (1) 423 | LCM(12, 21, 15) = 420; HCF = 3. Sum = 423.
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| 14 | (4) ∞ | There are infinite rational numbers between any two real numbers.
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| 15 | (3) 2 | 18=32. Multiplying by 2 gives 6 (rational).
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| 16 | (1) 1.02 | 101÷99=1.020202...
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| 17 | (1) 3/2 | Product of zeroes =−(−6)/a=4⟹6/a=4⟹a=1.5 or 3/2.
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| 18 | (4) −6/5 | k(2)2+3(2)+k=0⟹5k+6=0⟹k=−6/5.
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| 19 | (2) p=r | For reciprocals 2 and 1/2, the product is 1, so r/p=1⟹p=r.
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| 20 | (4) ab=6 | For parallel lines: a/3=2/b=9/18⟹ab=6.
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| 21 | (1) Unique | Lines x=0 (y-axis) and y=3 intersect at exactly one point (0, 3).
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| 22 | (3) 20 m, 16 m | L=W+4; L+W=36. Solving gives 20 and 16.
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| 23 | (1) x=19,y=−14 | Solved via substitution or elimination.
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| 24 | (3) k<4 | For distinct roots, b2−4ac>0⟹16−4k>0⟹4>k.
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| 25 | (1) 5, 12 | x2+(x+7)2=132. Solving the quadratic gives x=5. +1
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| 26 | (1) x2−6x+4=0 | Roots are 3±5. Sum = 6, Product = 9−5=4.
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| 27 | (2) (x+1)2=2(x−3) | This expands to x2+2x+1=2x−6, which is a quadratic.
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| 28 | (3) 17 | Common difference is 5. 12+5=17.
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| 29 | (2) 3:1 | Based on a+17d/a+10d=3/2.
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| 30 | (1) -320 | S16=216[2(10)+15(−4)]=8(20−60)=−320.
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| 31 | (3) secα | (3−2)2+(0−tanα)2=1+tan2α=sec2α.
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| 32 | (2) (1, 7) | [(5−3)/2,(3+11)/2]=(1,7).
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| 33 | (1) 2nd | Negative x and positive y are in the second quadrant.
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| 34 | (4) 5:1 | Ratio is −x1:x2=−5:−1=5:1.
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| 35 | (4) 2+2 | Sides are 1, 1, and 2. Sum =2+2.
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| 36 | (3) 9 | Using Thales theorem: LC/AC=MC/BC⟹(x+3)/2x=(x+5)/(2x+3).
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| 37 | (2) 15 cm | Perimeter ratio = side ratio. 7.5/P=2/4⟹P=15.
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| 38 | (2) 135∘ | Exterior angle x=70∘+65∘=135∘.
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| 39 | (3) 13 m | Right triangle with sides 12m and 5m (11−6). Hypotenuse = 13.
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| 40 | (3) 12 cm | 152−92=225−81=144=12.
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| 41 | (2) Equal | Tangents from an external point to a circle are always equal.
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| 42 | (1) 154/3 | Area =(30/360)×π×142=(1/12)×(22/7)×196=154/3.
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| 43 | (2) 4:9 | Area ratio is the square of the circumference ratio: 22:32=4:9.
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| 44 | (2) 121 cm2 | TSA =πrl+2πr2=π(3.5)(4)+2π(3.5)2=44+77=121. +1
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| 45 | (1) 1:3:2 | Vol. Ratio: 31πr2h:πr2h:32πr3. Since h=r, ratio is 1/3:1:2/3.
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| 46 | (4) 36 | 4πr2=48⟹πr2=12. TSA of hemisphere =3πr2=3(12)=36.
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| 47 | (3) 1 | cot30∘=3⟹3a=3⟹a=1.
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| 48 | (2) 105∘ | B=45∘; A−B=60∘⟹A−45=60⟹A=105∘.
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| 49 | (4) a/b | sinθ=1−cos2θ=1−(b2−a2)/b2=a2/b2=a/b.
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| 50 | (3) k2+1k2−1 | Standard identity derived from cosec2θ−cot2θ=1.
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AP POLYCET 2026 Physics Key with Short Explanations[Set B]
This Key is prepared by APTEACHERS within the short span of time. Hence there may be some errors. Hence verify with the official Answer Key| Q. No. | Answer | Explanation/Hint |
| 51 | (1) n times | Magnetic field is proportional to the number of turns. +1
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| 52 | (4) Bar magnet | A solenoid creates a magnetic field identical to a bar magnet.
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| 53 | (2) Oersted | Hans Christian Oersted discovered electromagnetism in 1820.
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| 54 | (4) MRI scanning | Magnetic Resonance Imaging uses internal magnetic fields.
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| 55 | (1) Live wire | Red insulation traditionally denotes the live (phase) wire.
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| 56 | (2) Electric fuse | Fuses break the circuit during overloading to protect appliances.
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| 57 | (2) Parallel | Domestic appliances are connected in parallel to ensure independent operation.
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| 58 | (3) Increases heavily | Short circuits cause resistance to drop, spiking the current.
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| 59 | (4) 220 V | Standard domestic voltage in India is 220V.
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| 60 | (3) Wood | Wood does not allow light to pass through.
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| 61 | (1) 33∘ | Angle of incidence equals angle of reflection (i=r). +1
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| 62 | (3) R=2f | Radius of curvature is twice the focal length.
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| 63 | (2) -20 cm | m=−v/u=−2⟹v=2u=−60. 1/f=1/v+1/u⟹f=−20. +1
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| 64 | (1) r>i | Light bends away from the normal when entering a rarer medium.
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| 65 | (1) 6 m | Apparent depth = Real depth /n=8/(4/3)=6 m. +1
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| 66 | (1) Biconcave | Surfaces curved inward describe a biconcave lens.
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| 67 | (3) At principal focus | Parallel rays from infinity converge at the focus.
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| 68 | (2) 60 cm | 1/v−1/u=1/f⟹1/v−1/(−30)=1/20⟹v=60. +1
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| 69 | (1) Convex 4D, f=0.25 | f=1/P=1/4=0.25 m. Convex power is positive.
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| 70 | (2) 25 cm | Standard least distance for distinct vision in adults.
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| 71 | (4) Accommodation | The eye's ability to focus on different distances.
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| 72 | (1) Pupil | The pupil adjusts size to control light entry.
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| 73 | (3) In front of retina | Myopia causes light to focus before reaching the retina.
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| 74 | (3) Cornea has rods/cones | Rods and cones are in the retina, not the cornea.
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| 75 | (2) Dispersion | Splitting white light into VIBGYOR.
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| 76 | (4) Atm. refraction | Changes in air density cause starlight to bend.
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| 77 | (4) Violet | Violet has the shortest wavelength and highest deviation.
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| 78 | (1) Red | Red light has the longest wavelength in the visible spectrum.
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| 79 | (1) Least scattered | Long wavelength red light is least scattered by particles. +1
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| 80 | (3) Coulomb | S.I. unit of charge. +1
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| 81 | (2) Only (b) is true | Voltmeter is parallel; Ammeter must be in series. +1
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| 82 | (1) 1 coulomb | Q=I×t⟹1A×1s=1C.
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| 83 | (4) Potential difference | Definition of Voltage (V=W/Q).
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| 84 | (4) 2 A | I=V/R=6/3=2 A. |
| 85 | (2) R∝1/A | Resistance is inversely proportional to cross-sectional area.
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| 86 | (1) 24 Ω | Highest resistance is achieved in series (2+4+6+12=24).
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| 87 | (2) Prop. to resistance | H=I2Rt. |
| 88 | (4) Electric current | P=V×I. |
| 89 | (3) 3.6×106 J | 1000W×3600s=3.6MJ.
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| 90 | (4) Outside S to N | Outside a magnet, lines go from North to South.
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AP POLYCET 2026 Chemistry Key with Short Explanations[Set B]
This Key is prepared by APTEACHERS within the short span of time. Hence there may be some errors. Hence verify with the official Answer Key| Q. No. | Answer | Explanation/Hint |
| 91 | (4) H2O | Water is a covalent compound.
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| 92 | (3) Catenation | Carbon's ability to form long chains with itself.
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| 93 | (2) CH4 | Methane is the primary component of biogas.
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| 94 | (2) -CHO | Functional group for aldehydes.
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| 95 | (2) Substitution | Chlorine replaces a hydrogen atom in methane.
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| 96 | (1) Oxidation | Adding oxygen to ethanol converts it to ethanoic acid.
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| 97 | (3) Ethyne | Also known as acetylene, used in oxy-acetylene welding.
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| 98 | (1) 5-8% Acetic acid | Standard composition of vinegar.
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| 99 | (3) Methyl alcohol | Methanol is added to ethanol to make it undrinkable.
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| 100 | (2) CH3OH(l) | Methanol synthesis from syngas.
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| 101 | (4) Ca(OH)2 | Slaked lime is used for white washing.
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| 102 | (4) All of these | All listed reactions involve a single reactant breaking down.
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| 103 | (2) MnO2 reduced | MnO2 loses oxygen to become MnCl2.
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| 104 | (2) Antioxidants | These prevent the oxidation of fats and oils.
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| 105 | (4) Displacement | Aluminum displaces iron from its oxide.
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| 106 | (3) CH3COOH | Acetic acid is a weak acid and dissociates partially.
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| 107 | (1) Gastric juice | Highly acidic environment (pH ≈ 1.5-3.5).
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| 108 | (3) Ca hydroxyapatite | The crystalline mineral that makes up tooth enamel.
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| 109 | (2) Lactic acid | Found in curd and fermented milk products.
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| 110 | (4) Neutral | Strong acid + Strong base results in a pH of 7.
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| 111 | (2) NaOH,Cl2,H2 | Electrolysis of brine produces these three.
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| 112 | (3) Soda + Tartaric | Tartaric acid neutralizes the bitter sodium carbonate.
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| 113 | (1) Na2CO3 | Washing soda (soda ash) is a key ingredient in glass.
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| 114 | (3) CaSO4⋅21H2O | Calcium sulfate hemihydrate.
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| 115 | (4) All of these | Carbon, Sulfur, and Iodine are all non-metals.
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| 116 | (3) Both HCl/NaOH | Al2O3 is amphoteric (reacts with acids and bases).
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| 117 | (3) Na, Ca, Mg, Al | Highly reactive metals at the top of the activity series.
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| 118 | (2) Hg | Cinnabar is Mercury(II) sulfide (HgS).
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| 119 | (1) Anode | Impure metal dissolves from the anode.
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| 120 | (4) All of these | Galvanizing, anodizing, and alloying all prevent rust.
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How to Download AP POLYCET 2026 Official Answer Key [Soon]
Here is the Step by Step Process to download the AP Polycet Answer Key
- To download the AP POLYCET answer key, candidates can follow these step-by-step instructions:Start by visiting the official AP POLYCET website i.e. polycetap.nic.in.
- Look for the link labelled ‘AP Polycet 2024 Answer Key’ on the homepage or under the ‘Notifications’ or ‘Examinations’ section.
- Once you find the link, click on it. You may need to select your exam paper code if multiple keys are released for different exams.
- The answer key will typically be available in PDF format. Download the document to your device.
- It’s advisable to print out the answer key for easier comparison with your answers or save it for future reference.
AP Polytechnic Answer Key Objection Process
The State Board first will release the provisional answer key for this exam. After the release of the AP Polytechnic Answer Key, the board will provide a chance for candidates to submit objections against it. The Board will allow a specific time frame for objection submission.To submit objections, you have to pay a certain amount of fee and also to board may request valid proof of your objection. After receiving objection the officials will review it and publish the final solution key based on changes made in it.
AP POLYCET Exam Analysis 2026
A detailed analysis of the AP POLYCET 2026 exam is provided here for the reference of the aspirants who have appeared for the exam:
|
Parameters | Details |
|---|---|
Overall Difficulty Level | Moderate |
Mathematics Difficulty Level | Moderate to Difficult |
Physics Difficulty Level | Moderate |
Chemistry Difficulty Level | Easy to Moderate |
Expected Number of Good Attempts | 85+ |
Was the Paper time-consuming? | Yes, it was lengthy |
