APRJC CET 2026 Answer Key & Question Paper [Download]. APRJC entrance exam for Admission into AP Residential Junior colleges was conduced on 24th April 2026. The 10th Students appeared for APRJC CET 2026 for Admissions. The Answer Key for APRJC 2026 Question Paper is made available for all. The APRJC 2026 Answer Key enables the Students to count their correct answers and have an idea of their score. Note that this is not Official Answer Key. It is the APRJC 2026 Answer key prepared by Experts. There might be some errors. APRJC CET 2026 - Questions & Solutions
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APRJC CET 2026 Answer Key & Question Paper [Download] with explanations
The Andhra Pradesh Residential Junior Colleges Common Entrance Test (APRJC CET) is one of the most important entrance exams for students who have completed their 10th class and want to pursue Intermediate education in top residential colleges across Andhra Pradesh. Conducted by the Andhra Pradesh Residential Educational Institutions Society, this exam opens the door to quality education, discipline, and strong academic foundations.🔹 What is APRJC 2026 Entrance Exam?
APRJC CET is a state-level entrance exam that provides admission into Andhra Pradesh Residential Junior Colleges (APRJCs). These colleges are known for:- High-quality teaching standards
- Free or low-cost education
- Residential facilities (hostel & food)
- Strong focus on competitive exams like NEET, JEE, CA Foundation
APRJC CET 2026 Exam Pattern
The APRJC Entrance Exam is designed to test students’ basic understanding of 10th class subjects.
- Mode: Offline (OMR-based)
- Type: Objective (Multiple Choice Questions)
- Duration: 2 hours 30 minutes
- Subjects:
- MPC: Maths, Physical Science
- BiPC: Biological Science, Physical Science
- MEC/CEC: Maths, Social Studies, English
APRJC CET 2026 Answer Key and Solutions Explanation
Here is the APRJC CET 2026 Answer key with explanations for Mathematics MPC Stream Exam.
All the Questions and Answers along with their solutions and short explanations are given.
APRJC-CET 2026 ANSWER KEY
Group: MPC / EET | Total Questions: 150
PART-I: GENERAL ENGLISH
1. Write the synonym of the word 'upbraiding'.
Solution: (1) — 'Upbraiding' means to criticize or find fault with someone, making 'Scolding' the correct synonym.
2. The river mentioned in the lesson 'Coorg' is
Solution: (1) — In the lesson 'Coorg', the Kaveri river is the primary water source mentioned.
3. What was Valli's wish?
Solution: (1) — Valli's deepest desire was to take a ride on the bus that traveled between her village and the town.
4. Gautama Buddha asked Kisa Gotami to bring ______ from the house where no one died.
Solution: (1) — Buddha asked Kisa Gotami for mustard seeds to teach her that death is universal.
5. Find the right prefix for the word given in the sentence: No one is ______touched by death.
Solution: (3) — The prefix 'un-' added to 'touched' (untouched) means not affected.
6. A letter written to a friend is
Solution: (2) — Letters to friends and family are categorized as informal letters.
7. What is the central theme of the poem 'Fire and Ice'?
Solution: (1) — In Robert Frost’s poem, 'fire' represents desire and 'ice' represents hatred.
8. Choose the right article: She ate ______ apple before leaving home.
Solution: (2) — 'Apple' starts with a vowel sound, so the article 'an' is required.
9. Fill in the blank with right preposition: He is afraid ______ darkness.
Solution: (4) — 'Afraid of' is a standard prepositional phrase.
10. Choose the right phrasal verb: Scientists are on the brink of a major ______ in cancer research.
Solution: (1) — A 'breakthrough' refers to a sudden, dramatic, and important discovery.
11. Courage was not the absence of fear, ______
Solution: (4) — This is a direct quote from Mandela: courage is the triumph over fear.
12. Combine the sentences using Relative Clause 'whose': Lencho prayed to God. His eyes sees into our minds.
Solution: (2) — 'Whose' is used as a relative pronoun to show possession (God's eyes).
13. The phrase 'The Dust of Snow' by Robert Frost portrays
Solution: (4) — The 'Dust of Snow' acts as a symbol of changing a person's mood.
14. What made the seagull dive into the air?
Solution: (4) — The seagull's hunger and the mother's baiting with fish combined to force the dive.
15. Choose the right compound word.
Solution: (1) — 'Stiff-backed' is a compound word (adjective + noun).
16. 'It sits looking over harbour and city.' What is the figure of speech of "It"?
Solution: (2) — 'It' refers to the fog 'sitting' and 'looking', which are human traits (Personification).
17. Find the antonym of apathy: "During the day, he began to lose his apathy and took a keen look at his surroundings."
Solution: (4) — 'Apathy' means lack of interest; 'Passion' is the opposite.
18. Pick out the right adjective: How would you describe a good detective serial on television?
Solution: (2) — 'Thrilling' is the correct adjective to describe the nature of a detective serial.
19. The girl read the poem aloud. (Change the voice)
Solution: (3) — The past simple passive follows: Subject + was + V3 + by agent.
20. Our car ran out of petrol just now. (Underlined meaning)
Solution: (3) — 'Ran out of' means the supply was exhausted or used up.
21. Mandela said, "I knew my people were not free". (Reported Speech)
Solution: (4) — In reported speech, 'said' becomes 'said that', and 'knew' shifts to 'had known'.
22. Choose the right closing remarks for a formal letter.
Solution: (2) — 'Sincerely yours' is the standard formal closing.
23. Edit the underlined: "He is the most want criminal."
Solution: (2) — 'Wanted' is the adjective form used to describe a criminal.
24. What kind of statement is: "You should return the goods if undelivered."
Solution: (1) — The use of 'should' suggests a recommendation or piece of advice.
25. The word 'Chai' or 'Chini' is originated from ______ language.
Solution: (2) — The words 'Chai' and 'Chini' are Chinese in origin.
26. Choose the wrongly spelt word.
Solution: (3) — The correct spelling is 'fascinate' (includes a 'c').
27. Coorgi homes have a tradition of ______
Solution: (1) — 'Hospitality' is the noun form required to complete the phrase.
28. Choose the meaning of the phrase 'fly the coop'.
Solution: (4) — 'Fly the coop' is an idiom meaning to escape or leave a place.
29. Which poem is written in the style of a ballad?
Solution: (4) — This poem uses a rhythmic, story-telling style typical of a ballad.
30. "It is an old fashioned outfit." (Underlined adjective type)
Solution: (2) — 'Old-fashioned' expresses an opinion or judgment about the outfit.
31. Antonym of: "The monstrous terror seized him and his heart stood still."
Solution: (4) — 'Monstrous' implies something horrible; 'Pleasant' is the opposite.
32. 'A Long Walk to Freedom' was Nelson Mandela's ______
Solution: (2) — Nelson Mandela wrote about his own life (Autobiography).
33. What is the noun form of the word 'rebel'?
Solution: (2) — 'Rebellion' is the noun form of the verb/noun 'rebel'.
34. My brother is addicted ______ video games.
Solution: (1) — 'Addicted to' is the correct fixed preposition.
35. What worried the parents as time was running out?
Solution: (1) — Parents are worried because only 10 days remain to finish the work.
36. Two objections raised regarding holiday homework?
Solution: (2) — Complaints were about the high level and the large quantum.
37. Holiday homework special classes are for ______
Solution: (2) — These classes are for well-off parents who lack time.
38. That ______ makes it necessary that quality homework is done.
Solution: (3) — Marks added to internal assessments make quality imperative.
39. Word meaning 'mandatory' for parents:
Solution: (2) — 'Imperative' in this context means absolutely necessary.
40. Idiom meaning: "not to lose heart"
Solution: (2) — To 'lose heart' is an idiom for losing hope.
41. Difference between a hyena and a crocodile?
Solution: (4) — Hyenas are described as smiling and crocodiles as weeping.
42. Find the synonym of 'overwhelmed'.
Solution: (4) — In this context, it implies a deep, expressive feeling.
43. Mij tugged me to this wall. (Habitual past)
Solution: (1) — 'Would' is used to express a past habitual action.
44. Who helped Lencho with money after the storm?
Solution: (4) — The Postmaster organized the collection to help Lencho.
45. A spinning fast wind movement is:
Solution: (3) — A whirlwind is defined by its spinning, fast movement.
46. Stephen Chubukov was ______
Solution: (2) — In the play, Chubukov and Lomov are neighboring land owners.
47. Activity in 'A Baker from Goa':
Solution: (3) — The author remembers children collecting bread bangles.
48. In 'Amanda' the girl feels curtailed of ______
Solution: (1) — Amanda feels her freedom is curtailed by constant instructions.
49. Personal writings of a person is called ______
Solution: (2) — Personal daily writings are defined as a diary.
50. "Lencho was an ox of a man." (Figure of speech)
Solution: (2) — Comparing a man to an ox without 'like' is a metaphor.
PART-II: MATHEMATICS
51. If the sum of n terms of an A.P. is 2n2 + 5n, then its nth term is:
Solution: (3) — nth term an = Sn - Sn-1. For 2n2 + 5n, this simplifies to 4n+3.
52. If the arithmetic mean of a and b is (an + bn) / (an-1 + bn-1), then n is:
Solution: (2) — For the expression to equal (a+b)/2, n must be 1.
53. In ΔABC, ∠C = 90°. BC = 15 cm, AC = 20 cm. Length of CD (perpendicular on AB):
Solution: (1) — Area = ½ × 15 × 20 = ½ × 25 × CD. Solving gives CD = 12.
54. In ΔABC, DE || BC. AD = 2 cm, DB = 3 cm, DE = 4 cm. Value of BC:
Solution: (2) — By Basic Proportionality Theorem, AD/AB = DE/BC → 2/5 = 4/BC → BC = 10.
55. Ratio of side and height of an equilateral triangle?
Solution: (2) — Height h = (√3/2)s. Ratio s : h = 2 : √3.
56. In ΔABC, XY || BC divides the triangle into equal areas. Ratio AX/BX is:
Solution: (1) — Area ratio is 1/2, so side ratio AX/AB = 1/√2. Thus AX/BX = 1/(√2 - 1).
57. Diagonals of a rhombus are 24 cm and 32 cm. Perimeter is:
Solution: (3) — Side s = √(122 + 162) = 20. Perimeter = 4 × 20 = 80.
58. If A(-2,-1), B(a,1), C(4,b) and D(1,2) are vertices of a parallelogram, (a,b) =
Solution: (1) — Diagonals bisect each other. Midpoint comparison gives a=1 and b=4.
59. In what ratio does the x-axis divide (-3, 4) and (a, -5)?
Solution: (2) — Ratio = -y1 : y2 = -4 : -5 = 4 : 5.
60. Trisection points of segment joining (0, 0) and (9, 12)?
Solution: (1) — Section formula for 1:2 and 2:1 ratios gives (3,4) and (6,8).
61. Distance between (a cos θ + b sin θ, 0) and (0, a sin θ - b cos θ):
Solution: (4) — Distance formula simplifies to √(a2 + b2).
62. If sin 3A = cos 15A, then A (in degrees) is:
Solution: (1) — 3A + 15A = 90° → 18A = 90° → A = 5°.
63. √[(1 + sin θ)/(1 - sin θ)] + √[(1 - sin θ)/(1 + sin θ)] =
Solution: (2) — Simplification via rationalization gives 2 / cos θ.
64. tan 1° tan 2° tan 3° ... tan 89° =
Solution: (1) — All terms pair up to 1, including tan 45° = 1.
65. Ratio of pole and shadow is 1 : √3. Elevation angle?
Solution: (3) — tan θ = 1 / √3 → θ = 30°.
66. Tower 12 m high, depression 30°. Distance from top to ground point:
Solution: (2) — sin 30° = 12 / Hypotenuse → H = 24.
67. Pole 15 m high, shadow 5√3 m. Elevation angle:
Solution: (4) — tan θ = 15 / 5√3 = √3 → θ = 60°.
68. If sec θ = (m + n) / (2√mn), then tan θ =
Solution: (3) — Determined by using the identity tan2θ = sec2θ - 1.
69. Concentric circles radii a, b (a > b). Length of AB touching inner circle:
Solution: (1) — Chord AB = 2 × AC = 2√(a2 - b2) by Pythagoras.
70. Tangents to a circle parallel to a secant:
Solution: (3) — There are exactly 2 tangents parallel to any given secant.
71. Point P, tangent 8 cm, radius 6 cm. Length OP:
Solution: (4) — In right triangle, OP2 = 82 + 62 = 100, so OP = 10.
72. Tangents PA, PB inclined at 80°. ∠POA =
Solution: (2) — ∠POA = ½(180° - 80°) = 50°.
73. Minute hand 21 cm. Distance moved by tip in 1 hour:
Solution: (1) — Distance = Circumference = 2 × π × 21 = 42π.
74. Area of circle inscribed in square of side 6 cm:
Solution: (4) — Radius r = 3. Area = πr2 = 9π.
75. Ratio of curved surface areas: Sphere : Cylinder : Cone?
Solution: (3) — 4πr2 : 4πr2 : πr2√5 → 4 : 4 : √5.
76. Max cone volume from cube of edge 4.2 cm:
Solution: (4) — V = ⅓π(2.1)2(4.2) ≈ 19.4.
77. Cubes edges 3, 4, 5 melted into one. New edge:
Solution: (3) — New volume = 27 + 64 + 125 = 216. New edge = 6.
78. Mean is 'p'. Multiply by 4, add 3. New mean:
Solution: (1) — Mean follows the transformation ax + b → 4p + 3.
79. Correct relation for: 2, 3, 0, -1, 1, 5, 6, 4, 5, 8, 11?
Solution: (3) — Calculating mean and median for this set shows they are equal.
80. Mean of 20 items is 15. Item 15 misnoted as -15. Correct mean:
Solution: (2) — Sum adjustment: 300 - (-15) + 15 = 330. New mean = 16.5.
81. Average of Median(2,8,3,7,4,6,7) and Mode(2,9,3,4,9,6,9):
Solution: (4) — (6 + 9) / 2 = 7.5.
82. die thrown twice. Prob sum is odd?
Solution: (1) — 18 odd sums out of 36 total = 1/2.
83. Two coins tossed. Prob at least one head?
Solution: (3) — Outcomes HH, HT, TH out of 4 = 3/4.
84. Prob drawing red king from deck?
Solution: (2) — 2 red kings / 52 cards = 1/26.
85. 12 bad pens in 132 good. Prob picking a good pen?
Solution: (4) — 132 / 144 = 11/12.
86. LCM is 14x HCF. LCM + HCF = 600. One num 280, other?
Solution: (1) — HCF = 40, LCM = 560. Product logic: 280 × other = 560 × 40 → other = 80.
87. Least prime factor of a=3, b=7. Least factor of (a+b)?
Solution: (4) — Sum of two odds is even, so least factor is 2.
88. 1192 - 1112 is:
Solution: (2) — Product (8 × 230) is clearly composite.
89. zeros of x2-4x+1 are a,b. 1/a+1/b-ab =
Solution: (3) — (a+b)/ab - ab = 4/1 - 1 = 3.
90. One zero of 2x2-3x+k is reciprocal of other. k =
Solution: (1) — Product k/2 = 1 → k = 2.
91. a,b zeros of x2+px+q. poly with zeros 1/a, 1/b?
Solution: (3) — Reciprocal transformation results in qx2+px+1.
92. k for parallel: 4x+6y-1=0 and 2x+ky-7=0?
Solution: (2) — 4/2 = 6/k → k = 3.
93. Equations x=0 and x=-7 have:
Solution: (4) — Parallel vertical lines never intersect.
94. 3/bench leaves 1 kid. 4/bench leaves 1 bench. Count?
Solution: (1) — Solving the system gives 16 students and 5 benches.
95. α, β roots of x2-px+q=0. α3β2 + α2β3 =
Solution: (4) — α2β2(α+β) = q2(p) = pq2.
96. If (x-3)(x-5) = ax2+bx+c, value of a-b+c =
Solution: (3) — Set x = -1: (-4)(-6) = 24.
97. Roots of kx2+(k-1)x+(k-1)=0 are equal. k =
Solution: (3) — Discriminant = 0 results in k = 1.
98. If x = √[3+√(3+√3+...)], then:
Solution: (4) — x2 = 3 + x → x2-x-3=0.
99. A.P. Sum of m terms = n, n terms = m. Sum of (m+n) terms?
Solution: (2) — Standard property: Sm+n = -(m+n).
100. Sum of 10 terms: √3 + √12 + √27 + √48 + ...
Solution: (1) — √3(1+2...+10) = 55√3.
PART-III: PHYSICAL SCIENCES
101. A (cold water), B (hot water only), C (no reaction). Order:
Solution: (1) — Reactivity decreases from A to B to C.
102. Which doesn't liberate H2 gas with acids?
Solution: (3) — Copper is below hydrogen in the reactivity series.
103. Metal that conducts electricity but is not ductile?
Solution: (4) — Mercury is liquid; it conducts but cannot be wires.
104. Which metal oxide is amphoteric?
Solution: (3) — Aluminum oxide reacts with both acids and bases.
105. Metal soft enough to cut with a knife?
Solution: (1) — Sodium is a soft alkali metal.
106. Metal used in anodising:
Solution: (4) — Anodizing thickens the oxide layer on Aluminum.
107. Which is NOT an ionic compound?
Solution: (2) — HCl is polar covalent.
108. 6-carbon alkane (single bonds) formula:
Solution: (2) — Follows CnH2n+2.
109. Ethanol on strong oxidation gives:
Solution: (2) — Ethanol oxidizes to ethanoic acid.
110. same homologous series?
Solution: (1) — Both are alkanes.
111. Ethene + Hydrogen → Ethane. This is:
Solution: (2) — Adding H to unsaturated hydrocarbon.
112. Produces sweet smelling substance?
Solution: (1) — Produces esters.
113. Covalent bonds in C4H10?
Solution: (3) — 3 C-C bonds + 10 C-H bonds = 13.
114. Ray A(n=1.33) → B(n=1.50). Ray will:
Solution: (1) — Rarer to denser medium bending.
115. Highest light speed medium?
Solution: (2) — Lowest refractive index allows highest speed.
116. f = +25 cm. Lens and Power?
Solution: (2) — P = 100/25 = +4D. Positive = Convex.
117. FALSE regarding convex lens?
Solution: (4) — Concave lenses always form diminished virtual images.
118. Real same-size image at dist between obj and img?
Solution: (4) — Total dist = 2f (obj to lens) + 2f (lens to img) = 4f.
119. Incidents at 0° with normal. Refraction and shift?
Solution: (3) — No deviation for normal incidence.
120. Incidents pass through 'C' of concave mirror. angle?
Solution: (3) — Reflects back along same path (0°).
121. corrective lens -2.5D. Far point?
Solution: (2) — f = 1/P = 40 cm.
122. Correct about Scattering of Light?
Solution: (2) — Red has long wavelength, scatters least.
123. muscles relaxed. Eye lens focal length approx?
Solution: (1) — Focal length is max at approx 2.5 cm.
124. delayed sunset occurs due to:
Solution: (2) — Light bends through the atmosphere.
125. Triangular prism (A=60°), min deviation 30°. n is:
Solution: (2) — n = sin(45)/sin(30) = √2.
126. Student table analysis. correct statement:
Solution: (3) — Healthy eye specs: 25 cm min, infinite far.
127. Resistivity: A(2e-8), B(5e-7), C(1e-6), D(8e-8). Max R?
Solution: (3) — C has the highest resistivity.
128. Parallel vs series resistance ratio for 4, 6, 12 Ω:
Solution: (4) — Parallel = 2, Series = 22. Ratio = 1:11.
129. Energy by 1 kW heater in 30 mins?
Solution: (1) — 1kW × 0.5hr = 0.5 kWh.
130. NOT electrical power formula:
Solution: (2) — IR2 is invalid.
131. Count of 176Ω parallel for 5A on 220V?
Solution: (4) — Total R = 44 Ω → 176/4 = 44.
132. Joule / Coulomb =
Solution: (3) — Volts = J/C.
133. Assertion: magnetic lines don't cross.
Solution: (1) — Field direction is unique at every point.
134. Property of proton changes in magnetic field?
Solution: (4) — Velocity and Momentum change as direction changes.
135. At short circuit, current ______
Solution: (3) — Zero resistance causes a current spike.
136. Left hand forefinger is:
Solution: (1) — Forefinger = Field.
137. Electron enters at right angles. Force direction:
Solution: (4) — Into the page per Left Hand Rule.
138. Rule for magnetic field around wire:
Solution: (1) — Right-hand thumb rule.
139. x + y in: 2Pb(NO3)2 → xPbO + yNO2 + O2
Solution: (2) — 2+4 = 6.
140. Balanced Al + HCl reaction:
Solution: (2) — Correct atom balance.
141. Quick lime + water reaction is:
Solution: (1) — Combination that releases heat.
142. CuO + C → Cu + CO. Oxidised?
Solution: (2) — Carbon gains oxygen.
143. Rancidity caused by:
Solution: (2) — Reaction with oxygen.
144. Volume ratio H to O in water:
Solution: (3) — 2 molecules H2 vs 1 molecule O2.
145. 2 NaHCO3 → A + H2O + B. A and B:
Solution: (2) — Thermal decomposition product.
146. pH=3 vs pH=5 acidity:
Solution: (3) — log scale difference.
147. Mix for neutral solution:
Solution: (1) — Strong acid + strong base.
148. Correct about acids in aqueous sol:
Solution: (2) — Release protons to form hydronium.
149. chemical name of POP:
Solution: (3) — Calcium sulphate hemihydrate.
150. Gases at anode and cathode:
Solution: (3) — Cl at anode, H at cathode.

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